Ariel B. answered 10/15/23
PhD (Physical Chemistry), MS (Theoret.Physics), 10+ yr. tutor. exp.
All blocks would move at same acceleration
a=Pulling force/(total mass of the blocks)=13N/(1kg+2kg+3kg)=13N/6kg=2.2m/s2
The force applied from the block2 to the block 3 would be the force needed to give the block 3 the acceleration a:
F3<=2=3kg x 2.2m/s2=6.6N
By 3rfNewtonian Law, the block 2 would pull on the block 1 with a force equal and oppositely directed to the force with which block1 would pull on block2 (which must be equal to (m2+m3)a= 5kg x 2.2m/s2=11N
Note: in the problem sig.figs requirements were not stated.
(If a standard sig.fig. policy is to be followed, only 1 sig. fig. must have been retained in all answers)