William W. answered 09/27/23
Experienced Tutor and Retired Engineer
The only force acting on the rocket is the force of gravity so the rocket will experience an acceleration of -9.8 m/s2 in the downward direction,
At the peak of the rocket's travel, it will have an instantaneous velocity of 0 m/s
For constant acceleration:
vf = vi + at where vf = 0 m/s (top of the rocket's travel), vi = 400 m/s, a = -9.8 m/s2, and t = the time in seconds from launch to the peak of the rocket's travel
0 = 400 + (-9.8)(t)
-400 = -9,8t
-400/-9.8 = t
t = 40.816 or rounded, t = 41 s
Also for constant acceleration:
y = (1/2)at2 + vi(t)
y = (1/2)(-9.8)(40.8162) + (400)(40.816)
y = -8163 + 16327
y = 8163 or rounded, y = 8200 meters