Ariel B. answered 09/28/23
PhD (Physical Chemistry), MS (Theoret.Physics), 10+ yr. tutor. exp.
Phoebe,
All the questions can be answered from the Lorentz Transformations (LT) between the 4-coordinates of an event A (x,recorded by an observer in K and those of the SAME EVENT A as observed by an observer in K' . Let K,K' be two intertidal RF, their origins at t=0 coinciding and their X-directions parallel to each other
If RF K' is moving relative to RF K along the X with Velocity V then, using the notations
β=V/C ;γ=(1-β^2), τ=Cxt the LT has the most symmetric and simple form:
τ(A)=γ-1[τ(A)'+βx(A)'] (1)
x(A)=γ-1[x(A)'+βτ(A)':] (2)
y(A)=y(A)' (3)
z(A)=z(A)' (4)
If a moving object A is observed in K and K'
then you can get the LT of velocity X-component (which is the only component you are asked) - derived below (result - in (8))
From (1) and (2)
dτ(A)=γ-1[dτ(A)'+βdx(A)'] (5)
dx(A)=γ-1[dx(A)'+βdτ(A)':] (6)
Let's call
β(A)=v(A)/C
β(A)'=v(A)'/C
So, β(A)=V(A)/C=(dx(A)/dτ(A)=[dx(A)'+βdτ(A)']/
[dτ(A)'+βdx(A)'] (7)
We could then formally divide both the numerator and the denominator in (7) dτ(A) to get
β(A)=[β(A)'+β]/[1+ββ(A)'] (8)
What you need to do is to correctly substitute the numbers and get back to the "normal" notations for the coordinates and velocity
t=τ/C ; v(A)=β(A)C; v(A)'=β(A)'C
Pay attention to the directions of v(A)' by using it proper sign (e g. is an object in K' thrown in negative direction of x, use negative sign of v(A)'
Good luck
Dr.Ariel
Ariel B.
09/29/23