Hello,
Please let me know if this works well for you, or if you'd like more insight on this problem.
Using your Pythagorean identities,
We know the following:
sin2(x) + cos2(x) = 1.
Lets go ahead and multiply both sides by (1/cos2(x)).
So, now we have:
--> [1/cos2(x)][sin2(x) + cos2(x)] = 1(1/cos2(x)) Equation (1)
----> sin2x / cos2(x) + cos2(x)/cos2(x) = 1/cos2(x) Equation (2)
Now, recall the identities:
tan(x) = sin(x)/cos(x) sec(x) = 1/cos(x)
After we square both sides of the equations, we now have the identities:
tan2(x) = sin2(x)/cos2(x) sec2(x) = 1/cos2(x)
Using these identities, we can further simplify equation (2) :
----> sin2x / cos2(x) + cos2(x)/cos2(x) = 1/cos2(x) Equation (2)
------> tan2(x) + 1 = sec2(x) Equation (3)
Subtract tan2(x) on both sides of the equation:
--------> 1 = sec2(x) - tan2(x) Equation (4)
Using algebra, we can foil out Equation (4):
----------> 1 = ( sec(x) + tan(x) ) ( sec(x) - tan(x) ) Equation (5)
Please let me know if this is well.
Best wishes.