Guy A. answered 09/20/23
Math and Physics Tutor
The first thing to look for is what you know, and that is the cheetah's
- initial speed (V0 = 0)
- final speed (Vf = 20)
- distance it travels (d = 48).
For part a, we want to use an equation that only has those variables and the acceleration because that is what we are solving for. Our best equation is:
Vf2 = V02 + 2ad
With this, we solve for the acceleration. I recommend only plugging in values that are zero until you have a final equation. It is a good habit to get into, and it makes everything easier. (You can also then use the final equation if you have the same situation)
Vf2 = 0 + 2ad
(Vf2) ⁄ (2d) = a
202 / (2*48) = a = 400/96
a = 25/6 m/s2
Solving for the time, we want to use an equation that has time in it. There are two options
- d = V0 t + (1/2) a t2
- Vf = V0 + 2ad
The second one is better in my opinion because you don't need to worry about doing a square root, but both work. I'll show both to be thorough, but equation 2 is easier, in my opinion.
- 1 d = V0 t + (1/2) a t2
d = 0 + (1/2) a t2
(2d)/a = t2
t = sqrt[(2d)/a]
t = sqrt[96/ (25/6)]
t = sqrt (576/25)
t = 24/5 s = 4.8 s
- 2 Vf = V0 + at
Vf = 0 + at
Vf / a = t
20 / (25/6) = t
120/25 = t
24/5 seconds = 4.8 seconds = t
Both options get the same answer. I hope this helps.