70 ft long and 60 feet wide at one corner. the rest of the land outside the building forms a parking lot. if the parking lot has area 5800 what are the dimensions of the entire plot of the land

Question

a square plot of land has a building 70 ft long and 60 feet wide at one corner. the rest of the land outside the building forms a parking lot. if the parking lot has area 5800 what are the dimensions of the entire plot of the land

Answer 1

A_bldg = 60 × 70 = 4200 ft²

A_lot =5800 ft²

So A_total = 4200 + 5800 = 10,000 ft²

It's a square plot of land so L = W

and L × W = L² = 10,000

So L = W = √(10,000) = 100

answer

The dimensions of the entire plot of the land are

L × W = 100 ft × 100 ft

Answer 2

Let x+70 be one side and y+60 be the other side of the square plot land

Since it is a square plot, x+70 = y+60

Area = (x+70)² = 5800

x²+140x+4900 = 5800

x²+140x-900=0

Using quadratic equation, x = -70±10√58 ≈ 6.16, -146.16

Use the positive value since this is a measurement.

Dimensions: x+70 ≈ 76.16 and y+60 = x+10 +60 ≈ 76.16

76.16 × 76.16 feet