A 0.394 m length

Question

A 0.394 m  length of current-carrying wire is placed in a uniform magnetic field oriented perpendicularly to the wire. The current is 3.64 A  and the magnitude of the magnetic field is 0.303 T . What is the force on the wire?

Answer 1

Hello Awo;

Since the wire is placed perpendicular to the magnetic field; we can directly use

F = B.I.L

F = 0.303T x 3.64A x 0.394m ≈ 0.43N which is perpendicular to both the B-field and the wire.