Mojde S. answered 09/13/23
Experienced Math Tutor Specialized in Algebra, Calculus, and Test Prep
1) first case
a= (v-u)/t
Where:
- a is the acceleration.
- v is the final velocity, which is 0 m/s (as the athlete comes to rest).
- u is the initial velocity, which depends on the athlete's speed while running.
- t is the time it takes to come to rest.
This formula describes the deceleration (negative acceleration) that the athlete experiences during the fall on the muddy field. so the answer for question 1 is a=(0-u)/t a=-u/t
2) second case
a= (v-u)/t
Where:
- a is the acceleration.
- v is the final velocity, which depends on the athlete's speed while running.
- u is the initial velocity, which is 0 m/s (as the athlete starts from rest).
- t is the time it takes to come to rest.
This formula describes the acceleration (positive) that the athlete experiences after starting back up running. so the answer for question 2 is a= (v-0)/t a=v/t