A ball is thrown down from a certain height with an initial velocity of 3.3 m/s. Estimate how fast it is going after 2.9 seconds

Answer 1

Assuming no wind resistance,

v = v₀ + at

where v₀ = 3.3 m/s, a = 9.8 m/s² and t = 2.9 s

so v = 3.3 + (9.8)(2.9) = 31.72 m/s

Answer 2