What will be the dimensions of b and c in this case if u = 18 and v = 4?

Question

The acceleration of a particle moving along the x axis may be determined from the expression a = bt^u + ct^v.

 What will be the dimensions of b and c in this case if u = 18

 and v = 4?

 (Use the following as necessary: L for length and T for time.)

b=

c=

Answer 1

for bt^u

the dimension of b must be acceleration divided by bt^u.

for ct^v

the dimension c must be divided acceleration by ct^v

given

u=18, v=4

hence the required dimensions are

b=a/t¹⁸, c=a/t⁴