wo charges q1 = −3.20 nC and q2 = +8.16 nC are at a distance of 1.47 µm from each other. q1 is fixed at its location while q2 is released from rest.

Question

(a) What is the kinetic energy of the charge q₂ when it is 0.340 µm from q₁? in joules

(b) The charge q₂ has a mass m₂ = 7.85 µg. What is its speed when it is 0.340 µm from q₁? in m/s

Answer 1

W = -ΔE_e = ΔE_k so k_eQ₁Q₂ *(1/r² - 1/r₀²) = 1/2 * mv²

The LHS is equal to the kinetic energy (r has to be in m and Q in coulombs

Then you can solve for v = sqrt(2E/m) with m in kg

Please consider a tutor. Take care.