
Mike D. answered 08/25/23
Effective, patient, empathic, math and science tutor
Complex zeroes come in pairs, so the other complex zero is the conjugate of -2i ie +2i (you switch the sign of the imaginary part).
So the four zeroes are -2i, +2i, 3, 3
So the polynomial factorises as a ( x-2i) (x+2i) (x-3) (x-3)
a is an arbitrary real constand which you can choose, choosing a=1 makes life easiest.
Then you have to multiply out the factorisation
(x-2i) (x + 2i) = x^2 +2ix -2ix -4i^2 = x^2 +4 (as i^2 = -1)
(x-3) (x-3) = x^2 -6x + 9
(x^2 + 4) (x^2 - 6x + 9)
x^2 -6x +9
x^2 x^4 -6x^3 +9x^2
4 + 4x^2 -24x + 36
Result : x^4 -6x^3 +13 x^2 -24x + 36