
Yefim S. answered 08/25/23
Math Tutor with Experience
1) f(x) = (- 8x4 - 16x3 - 2x2 - 4x - 8)/(x4 + 2x3+ x2 +8x - 9);
y =lim f(x) = - 8/1 = - 8, y = - 8 is H.A.
x→±∞
2) f(x) = - 8; - 8 x4 - 16x3 - 2x2 - 4x - 8 = - 8x4 -16x3 - 8x2 - 64x + 72; 6x2 + 60x - 80 = 0
3x2 + 30x - 40 = 0; x = (- 15 ± √225 + 120)/3 = (-15 ± √345)/3. So, we have 2 intersecion points
3) These points: (- 15 + √345)/3, - 8) or (- 15 - √345/3, - 8)