two blocks of mass 10 kg and 4 kg are placed over the surface of a lift accelerating upwards with acceleration 2m/s² contact force between the blocks is equal to​

Question

can you show a way using pseudo force too?

thankyou

Answer 1

Hello;

Let's take the mass on top, say 4kg.

Free body diagram

F_(contact) + mg = ma

F_(contact) - 4 x 9.8 = 4 x 2

F(contact) = 47.2N (upward)