QUADRATIC FIT! PLEASE HELP

Question

1) Find the quadratic the fits the table values:

x	-4	-2	0	2	4	6
y	3	-3	-6	-6	-3	3

2) comment on various applications using quadratic modeling.

Answer 1

x-1= a(y-k)^2 1 is the x coordinate of the vertex of a rightward opening horizontal parabola

a is very small close to zero, k is less than -6

plot the points and connect them with a smooth parabolic curve

Answer 2

y = ax² + bx + c; - 6 = c;

4a + 2b - 6 = - 6; 4a + 2b = 0; 2a + b = 0; 36a + 6b - 6 = 3; 12a + 2b = 3; 8a = 3; a = 3/8; b = - 3/4;

y = 3x²/8 - 3x/4 - 6