
Mark M. answered 07/12/23
Mathematics Teacher - NCLB Highly Qualified
r = 5 cos θ + 5 sin θ
r = 5 (x / r) + 5 (y / r)
r = (5x / r) + (5y / r)
r = (5x + 5y) / r
r2 = 5x + 5y
x2 + y2 = 5x + 5y
Kambria B.
asked 07/12/23A) x2 + y2 + 5y = 5x
B) x2 + y2 - 5y = 5x
C) x2 + y2 = 0
D) None of the above
Mark M. answered 07/12/23
Mathematics Teacher - NCLB Highly Qualified
r = 5 cos θ + 5 sin θ
r = 5 (x / r) + 5 (y / r)
r = (5x / r) + (5y / r)
r = (5x + 5y) / r
r2 = 5x + 5y
x2 + y2 = 5x + 5y
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Kambria B.
Thank you so much that was a huge help! I appreciated the quick but thorough walkthrough.07/12/23