Ben E.

asked • 06/23/23

A man drives a car a distance of 20km at an average speed of 44kmhr^-1. what must be his average speed for the next 220km if he is to cover the total distance in 9hours?

To get the average speed i had to first get the T1( as totaltime= T1 + T2)....do i have to add the average speed(V1 + V2?)

1 Expert Answer

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JACQUES D. answered • 06/23/23

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Find d2 and t2 and divide:

d2 = 220 km

t2 = 9 hrs - t1 and t1 = d1/v1 = 20 km/44 km/hr = .4545 hours


v2 = 220 km/(9-.4545 hours)


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Ben E.

Thank You, i was adding while i should have subtracted i'm grateful... please Sir And what are the idea or fundamental surrounding these problems mathematically ?
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06/23/23

JACQUES D.

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You can make a table for v,d, and t for situation 1, situation 2 and total. Remember v constant or average is always d/t for that interval or total. Also, you know that t1+t2 =ttot and d1+d2 = dtot. That should see you through any problem.
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06/24/23

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