Solve the following triangle. Round lengths to the nearest tenth and angle measures to the nearest degree.

Question

A=__°

B=52°

C=38°

a=8

b≈__

c≈__

Answer 1

A = 180 - 52 -38 = 180 -90 = 90, it's a right triangle

a is the side opposite A = the hypotenuse and the longest side

b is opposite B the 2nd longest side = the longest leg of the 2 legs = about 6.3

c is opposite C and is the shortest leg and shortest side = about 4.93 = about 4.9

it's a 4.9 - 6.3 - 8 right triangle, approximately

4.9 squared + 6.3 squared = almost 8 squared

Answer 2

Hi Richard P

In the problems you’ve listed you can use the following to calculate the missing angle. The sum of the angles in a Triangle is 180° so when you are given two of the angles in the triangle the missing angle is

180 -(sum of the two given angles)

Then if you have a side opposite one of your angles you can use the Law of Sines to calculate the other sides; The Law of Sines

a/sinA = b/sinB = c/sinC

Since you’ve listed the same type of problem several times please take look at the two problems I worked earlier and use them as examples to work on the other similar ones. Look up the Law of Sines and the sum of the angles in a triangle in your text or online for reference to see how these apply. Remember to draw a diagram.