Solve the following triangle. Round lengths of sides to the nearest tenth and angle measures to the nearest degree.

Question

A=43°

B=47°

C=__°

a≈__

b≈__

c=13

Answer 1

C = 90 degrees. it's a right triangle

c^2 = a^2 + b^2 = 169

a/sinA = b/sinB = 13/1 = 13

a = 13sinA = 13sin43= about 8.66 = about 9 rounded to up

b = 13sinB = 13sin47= about 9.51 = about 10 rounded to nearest integer

Answer 2