What is its acceleration with a proper sign? Keep 3 digits after the decimal point.

Question

At t1 = 5.0s an object's velocity is v1 = 8.790m/s to the EAST, and at t2 = 11.0s its velocity is

 v2 = 17.730 m/s to the WEST. Assuming a constant acceleration

Take EAST as the positive direction. 

Answer 1

Meagan - to solve this use kinematics equation V(t2) = V(t1) + at which would give:

Here V(t2) is negative 17.73 as EAST is positive and object is traveling WEST.

t2 - t1 = 6 seconds

-17.73 = 8.790 + 6a

Solve for a to get acceleration = -4.420 m/s2