An object's initial velocity is 1.34 m/s and it speeds up with a constant acceleration whose magnitude is 1.49 m/s^2. What is its velocity after a displacement of 15.0 m?

Answer 1

To find the final velocity of the object after a displacement of 15.0 m, we can use the following equation of motion:

v² = u² + 2as .........(1)

Initial velocity (u) = 1.34 m/s

Acceleration (a) = 1.49 m/s² (positive because it speeds up)

Displacement (s) = 15.0 m

v is the velocity after a displacement of 15.0 m

Substitute all values in (1), and we get:

v² = (1.34 m/s)² + 2 * 1.49 m/s² * 15.0 m

v² = 46.4956

v = √(46.4956)

v = 6.82 m/s

Therefore, the object's velocity after a displacement of 15.0 m is 6.82 m/s.