An object's initial velocity is 1.34 m/s and it speeds up with a constant acceleration whose magnitude is 1.49 m/s2. What is its displacement (in meters) from the initial moment to t = 7.50s?

Answer 1

To find the displacement of the object from the initial moment to t = 7.50 s, we can use the following kinematic equation:

s = ut + (1/2)at² .........(1)

where,

Initial velocity (u) = 1.34 m/s

Acceleration (a) = 1.49 m/s² (positive because it speeds up)

Time (t) = 7.50 s

s is the required displacement

Substitute all values in (1), and we get:

s = (1.34 m/s) * (7.50 s) + (1/2) * (1.49 m/s²) * (7.50 s)²

s = 51.96 m

Therefore, the displacement of the object from the initial moment to t = 7.50 s is approximately 51.96 meters.