Bobosharif S. answered 06/15/23
Mathematics/Statistics Tutor
You need just to solve the equation:
t^2-10t+25=0
(t-5)^2=0
t=5
Mark M.
No, 5 is a zero of multiplicity 2.06/16/23
Nikki G.
asked 06/15/23Consider the following.
h(t) =t^2-10t+25
find all the real zeros of the polynomial function.
Bobosharif S. answered 06/15/23
Mathematics/Statistics Tutor
You need just to solve the equation:
t^2-10t+25=0
(t-5)^2=0
t=5
Mark M.
No, 5 is a zero of multiplicity 2.06/16/23
Raymond B. answered 12/09/25
Math, microeconomics or criminal justice
t^2 -10t +25
factor
= (t-5)^2
real zeros are 5 and 5
graph the parabola and it is tangent to the x axis at x= 5, the point (5,0)
or you can say there's just one real zero, 5, with multiplicity 2
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Nikki G.
5 is an odd multiplicity, correct???06/15/23