Yefim S. answered 06/16/23
Math Tutor with Experience
Work done by sprinter: W = Ek = mv2/2; v = 2s/t. So, W = 2ms2/t2;
Average power Pav = W/t = 2ms2/t3 = 2·68.2kg·7.042m2/(1.63s3) = 1650.44 W
Llama N.
asked 06/15/23Starting a race, a 68.2 kg sprinter runs the first 7.04m in 1.6 sec. starting from rest and accelerating uniformly. What average power does the sprinter generate during the 1.6 sec interval?
Yefim S. answered 06/16/23
Math Tutor with Experience
Work done by sprinter: W = Ek = mv2/2; v = 2s/t. So, W = 2ms2/t2;
Average power Pav = W/t = 2ms2/t3 = 2·68.2kg·7.042m2/(1.63s3) = 1650.44 W
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