Inactive Tutor answered 12/23/25
FV = 1300(1+.075/4)^(4t)
where t = number of years
a) t = 1, FV = 1300(19/16)^4== $1390.00
b) t =2 FV = 1300(19/16)^8 =$1486.22
c) t 10 FV = 1300(19/16)^40=$2,538.90
rounded to nearest cent
Ben O.
asked 06/14/23If $1300 is invested at an interest rate of 6.75% per year, compounded quarterly, find the value of the investment after the given number of years. (Round your answers to the nearest cent.)
(a) 1 year
$
(b) 2 years
$
(c) 10 years
$
Inactive Tutor answered 12/23/25
FV = 1300(1+.075/4)^(4t)
where t = number of years
a) t = 1, FV = 1300(19/16)^4== $1390.00
b) t =2 FV = 1300(19/16)^8 =$1486.22
c) t 10 FV = 1300(19/16)^40=$2,538.90
rounded to nearest cent
The formula for compounding quarterly = A = P(1 + r/t)^nt
A is the amount after interest.
P is the initial investment
r is the yearly interest rate expressed as a number (divide by 100)
n is the number of compounding terms in the year
t is the number of years.
A A = 1300(1+.0675/4)^4 = about 1389.996265 = about 1390.00
B A = 1300(1+.0675/4)^8 = about 1486.22
C A = 1300(1+.0675/4)^40 = about 2538.90
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