Yefim S. answered 06/14/23
Math Tutor with Experience
T - λmg = ma; Mg - T = Ma; (T - λmg)/(Mg - T) = m/M; M(T - λmg) = m(Mg - T); T = Mmg(1 + λ)/(M + m)
T = 9.4·5·9.8(1 + 0.187)/(9.4 + 5) N = 37.97 N
Brandon A.
asked 06/13/23An apparatus is constructed such that a box with mass 5.00-kg resting on a table is attached to a string. The string passes over a pulley and is attached to a second box with mass 9.40 kg. If the coefficient of kinetic friction between the box on the table and the table is 0.187, what is the tension in the string? Assume this system starts to move despite any static friction.
Yefim S. answered 06/14/23
Math Tutor with Experience
T - λmg = ma; Mg - T = Ma; (T - λmg)/(Mg - T) = m/M; M(T - λmg) = m(Mg - T); T = Mmg(1 + λ)/(M + m)
T = 9.4·5·9.8(1 + 0.187)/(9.4 + 5) N = 37.97 N
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