Clive H. answered 06/14/23
40 years teaching experience, graduate in Physics, MA in Education,
Lets start by thinking about component of weight parallel to the plane - this is mg sin 36. The normal contact force is mg cos 36
Resultant force down the slope = mg sin 36 - f where is the frictional force
f = µ mg cos 36
So resultant force F down slope = mg sin 36 - µ mg cos 36, and acceleration = F/m (newton II)
a = g sin 36 - μ g cos 36
We need to isolate μ = (g sin 36 - a)/g cos 36)
If we use g = 9.8 m/s2 the answer is 0.64 to 2 s f