Yefim S. answered 06/11/23
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xC = (x1m1 + x2m2)/(m1 + m2) = (72m1 + 170·7/4m1)/(m1 + 7/4m1) = 134.3644 cm
Jessica F.
asked 06/11/23An object is placed at the position x1 = 72 cm and a second mass that is 7/4 times as large is placed at x2 = 170 cm. Find the location of the center of mass of the system.
m
Yefim S. answered 06/11/23
Math Tutor with Experience
xC = (x1m1 + x2m2)/(m1 + m2) = (72m1 + 170·7/4m1)/(m1 + 7/4m1) = 134.3644 cm
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Jessica F.
it says that the answer is off by a multiple of 10 thanks in advance06/11/23