Yefim S. answered 05/31/23
Math Tutor with Experience
l1 = l0(1 + λT1); l2 = l0(1 + λT2); l2 = l1(1 + λT2)/(1 + λT1).
l1 = 33.000m; T1 = (14 - 32)/1.8 = - 10°C; T2 = (93 - 32)/1.8 = 33.889°C; λ = 1.3·10-5C-1
l2 = 33.000·(1 + 1.3·10-5 ·33.889)/(1 - 1.3·10-5·10)m = 33.01883 m