Asma W.

asked • 05/25/23

Find the 4th term of (2x-5y)^7. Show how you came up with your answer.

How would I solve this using the Binomial Theorem?

1 Expert Answer

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Mark M. answered • 05/25/23

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Coefficient is 7! / (3!(7 - 3)! = (7*6*5*4) / (3*2*1) = 140

Term is (2x)4(-5y)3, expand this, then multiply for 140 or leave it as

140(2x)4(-5y)3

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AJ L.

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Small correction, 7!/(3!(7-3)!) = 7!/(3!4!) = (7*6*5*4*3*2*1)/(3*2*1*4*3*2*1)=(7*6*5)/(3*2*1)=35, so the term would be 35(2x)^4(-5y)^3.
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05/25/23

Asma W.

Thank you!
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05/25/23

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