(x+2)^2 + 4(x+2) =
(x+2)(x+2) + 4x + 8 =
x^2 + 4x + 4 + 4x + 8 =
x^2 + 8x + 12
Wsp D.
asked 05/18/23answers
x^2 + 4x + 12
x^2 + 4x + 1
x^2 + 16x + 12
x^2 + 8x + 12
(x+2)^2 + 4(x+2) =
(x+2)(x+2) + 4x + 8 =
x^2 + 4x + 4 + 4x + 8 =
x^2 + 8x + 12
Heather S. answered 05/18/23
Heather - Math Tutor
You have f(x) = x^2 + 4x and you have to evaluate for f(x+2).
You have to plug in (x+2) for every x value:
f(x + 2) = (x + 2)^2 + 4(x + 2)
Recall that (a + b)^2 = (a + b) * (a + b), so now you have:
f(x + 2) = (x + 2) * (x + 2) + 4(x + 2)
Now, distribute and use the foil method:
f(x + 2) = x^2 + 2x + 2x + 4 + 4x + 8
Combine like terms:
f(x + 2) = x^2 + 8x + 12
So your final answer will be f(x + 2) = x^2 + 8x + 12
Hope this helps!
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