
Sam B.
asked 05/18/23Can someone show a visual/video way to solve this problem
Draw the arrows on the following graph to represent the orientation of the following parametric equation
x(t)=3cos1/2t
y(t)=-5sin1/2t
https://drive.google.com/file/d/1jxrkF1JLlNo-50Uz24ucjWNxm2hAWxPc/view?usp=drivesdk
2 Answers By Expert Tutors
Muhammad Javed B. answered 05/27/23
Muhammad Javed B.
(t , x(t)) = {(30 , 24) (45 , 36) (60 , 48) (90 , 72) (180 , 145) (270,218) (360 , 291) } [ -63.11032386 -94.66548579 -126.22064772 -189.33097158 -378.66194316 -567.99291475 -757.32388633]05/27/23

Mark M. answered 05/19/23
Mathematics Teacher - NCLB Highly Qualified
Calculate x(t) for t = 60, 90, 120, 180. Draw vector to (t, x(t))
Calculate y(t) for t = 60, 90, 120, 180. Draw vector to (t, y(t))
This is for QI.
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Doug C.
Here is a start. Visit the following graph and use the slider on t to see if you can visualize the direction that the point on the parametric curve is moving. desmos.com/calculator/7oj20qyxap05/19/23