A discus is thrown from a height of 4 feet with an initial velocity of 65 ft/s at an angle of 44° with the horizontal. How long will it take for the discus to reach the ground?

Answer 1

y = 4 + 65sin44°·t - 16t² = 0; 16t² - 45.15t - 4 = 0; t = (45.15 + √45.15² + 256)/32 = 2.91 s

Answer 2

Only concerned with the y-component of the parametric equation.

y(t)=gt²/2+v_yt+y₀

g=-32.2 ft/s²

v_y=65sin(44°) ft/s

y₀ = 4 ft

-16.1t²+45.142t+4=0

t= -.09, 2.9 seconds

Use the positive value