x = 2√t --> t = (x/2)2 = x2/4
y = 4t2+3 --> y = 4(x2/4)2+3 = 4x4/16 + 3 = x4/4 + 3
x=3cost+1 --> t = arccos((x-1)/3)
y=2sint-3 --> y = 2sin(arccos((x-1)/3)) - 3 --> y = 2√(1-[(x-1)/3]2) - 3 --> y = 2√[1-(x-1)2/9] - 3
Hope this helped!
Sam B.
asked 05/16/23eliminate the parameter for the following parametric equations show all work simplify as you can
x(t)=2squrt t
y(t)=4t^2+3
and
x(t)=3cost+1
y(t)=2sint-3
x = 2√t --> t = (x/2)2 = x2/4
y = 4t2+3 --> y = 4(x2/4)2+3 = 4x4/16 + 3 = x4/4 + 3
x=3cost+1 --> t = arccos((x-1)/3)
y=2sint-3 --> y = 2sin(arccos((x-1)/3)) - 3 --> y = 2√(1-[(x-1)/3]2) - 3 --> y = 2√[1-(x-1)2/9] - 3
Hope this helped!
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