At that point, what is the acceleration?

Question

If st^3-5t^2+5t - 3, when will the velocity be 2 ft/s? At that point, what is the acceleration?

Answer 1

s(t) = t³-5t²+5t - 3

V(t) = 3t² -10t + 5

V(t) = 3t² -10t + 5 = 2

3t² -10t + 3 = 0

(3t-1)(t-3) = 0

t = 3, t = 1/3 (possible solutions)

a(t) = 6t - 10

IF we choose, t = 1/3 at the time of V(t) = 2ft/s, the acceleration will be -8 ft/s² if we choose t =3, then a(3) = 6 x 3 - 10 = 8 ft/s²