A 3.5 g dart is fired into a block of wood with a mass of 24.8 g. The wood block is initially at rest on a 1.7 m tall post.

Question

After the collision, the wood block and dart land 3.3 m from the base of the post. Find the initial speed of the dart.

Answer 1

mv = (M + m)v'; h = gt²/2; t = √2h/g; v' = s/t = s√g/2h; v = (M + m)/m·s√g/2h = (24.8 + 3.5)/3.5·√9.8/3.4) =

13.73 m/s