In preparing to shoot an arrow, an archer pulls a bowstring back 0.32 m by exerting a force that increases uniformly from 0 to 278 N. What is the equivalent spring constant of the bow?

Answer 1

The equation for the force of a spring is F=kx where F is force, k is the spring constant, and x is how far the spring was stretched. F and x are given in the question so plugging them in gives (278)=k(.32). If we then solve for k that gives k=(278)/(.32)= 868.75 N/m