Raymond B. answered • 5d
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Math, microeconomics or criminal justice
6500/5000= (1+.075/4)^4t
1.3 = 1.01875^4t
ln1.3)= 4tln1.01875
t= (ln1.3/4ln1.01875=
about 3.53 years
Ashley F.
asked • 05/09/23Precalculus question
Find the time required for an investment of 5000 dollars to grow to 6500 dollars at an interest rate of 7.5 percent per year, compounded quarterly.
Your answer is t= years.
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