pre calc question

Question

The doubling period of a bacterial population is  10 minutes. At time t=110 minutes, the bacterial population was 50000.

What was the initial population at time t=0?    

Find the size of the bacterial population after 5 hours.

Answer 1

50000 = a₀(2)^{110 / 10}, ,solve for a₀ and answer

A(300) = a₀(2)^{300 / 10}, substitue a₀ from above and calculate A(300)