The formula for MMS is MMS = (2/3)*log(S/S0) The log is base 10.
(2/3)*log(S/S0) = 4.2
For the 690 times as much energy quake it's (2/3)log(690S/S0) = (2/3)log(690 * S/S0) = (2/3)log(S/S0) + (2/3)log(690) = 4.2 + (2/3)log(690) = about 6.09
Ashley F.
asked 05/08/23One earthquake has MMS magnitude 4.2. If a second earthquake has 690 times as much energy (earth movement) as the first, find the magnitude of the second quake.
The formula for MMS is MMS = (2/3)*log(S/S0) The log is base 10.
(2/3)*log(S/S0) = 4.2
For the 690 times as much energy quake it's (2/3)log(690S/S0) = (2/3)log(690 * S/S0) = (2/3)log(S/S0) + (2/3)log(690) = 4.2 + (2/3)log(690) = about 6.09
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