
Bradford T. answered 05/08/23
Retired Engineer / Upper level math instructor
Use A=Pert
a) Initial size
1700=Pe35r
700 = Pe10r
Dividing
1700/700=e25r
r = ln(1700/700)/25 ≈ 0.0355
P = 700e-0.355 ≈ 491 bacteria
b) Doulbed
2 = e0.0355t
t = ln(2)/0.0355 = 19.525 minutes
c) After 120 minutes
491e0.0355(120) ≈ 34768 bacteria
d) When A=10000
10000 = 491ert
t= ln(10000/491)/0.0355 ≈ 84.9 minutes