A nichrome wire with a resistance of 12.3 is connected across the terminals of a 3.0 V flashlight battery. How much current is in the wire?

Answer 1

We know from Ohms law that Current is equal to Voltage times resistance, or I=VΩ

This problem tells us the value of resistance is 12.3, we assume the units is Ohms since it is unspecified. It also tells us the voltage is 3.0V

Therefore I=VΩ=(3.0)(12.3)=36.9 Amps