Inactive Tutor answered 04/26/23
Tutor
New to Wyzant
z1·z2 = 3/2cis(π/3 + π/6) = 3/2(cosπ/2 + isinπ/2) = 3/2i
Chloe W.
asked 04/26/23z1=1/2(cisπ/3) and z2=3(cosπ/6+isinπ/6)
Inactive Tutor answered 04/26/23
z1·z2 = 3/2cis(π/3 + π/6) = 3/2(cosπ/2 + isinπ/2) = 3/2i
Inactive Tutor answered 04/26/23
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