precalculus help

Question

All work must be shown clearly and neatly to receive full credit.

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.

Find the missing parts of the triangle.

1)

angle a corresponds to 30°(left side of the triangle). 4 is the hypotenuse .short leg is 2 and long leg of the triangle is missing. A is to the left of the triangle c is at the top and b is to right of the triangle.(i couldn't upload a picture sorry)

If necessary, round angles to the nearest degree and give exact values of side lengths.

2)Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary.

b = 19.1 ft

A = 23°10'

C = 95°10'

3)Find the missing parts of the triangle.

A = 30°

a = 7.65

b = 15.3

If necessary, round angles to the nearest degree and side lengths to the nearest hundredth.

Answer 1

1) long leg= 2sqr3, short leg=2, hypotenuse =4

other 2 angles are 60 and 90 degrees

60 is opposite the long leg

90 opposite the hypotenuse

30 opposite the short leg

2) A=23 degrees 10 minutes, C=95 degrees 10 minutes, B= 71 degrees 40 minutes

as A+B+C=180

b=19.1 feet

use the law of sines

c = bSinC/sinB

a = bSinA/sinB

once you have a, b and c, use Heron's formula to find the area

= sqr[s(s-a)(s-b)(s-c)] where s= half the perimeter = (a+b+c)/2

3) B=90, C=60, c=7.65sqr3= about 13.25

A=30, b=15.3, a=7.65