An object is placed in front of a diverging lens with a focal length of 16.4 cm. For each object distance, find the image distance and the magnification.

Question

(a) 32.8 cm

location:

magnification:

(b) 16.4 cm

location:

magnification:

(c) 8.2 cm

location:

magnification:

Answer 1

We can use the following equation: 1/f = 1/i + 1/o.

Here, f represents the focal length, i represents the image distance, and o represents the object distance.

If i (image distance) is a negative number, it is on the same side as the object

Magnification = image distance / object distance

a) 1/16.4 = 1/i + 1/32.8

i = 32.8 cm, image is across the lens from the object.

Magnification: 32.8/32.8 = 1

b) 1/16.4 = 1/i + 1/16.4

i = infinity, the image will be produced at the opposite side of the lens at an infinite distance

Magnification = 1

c) 1/16.4 = 1/i + 1/8.2

i = -16.4 cm, the image on the same side of the object

Magnification = 16.4/8.2 = 2