z = 3√2[cos(7π/4)+i·sin(7π/4)]
z = 3√2[√2/2 + i(-√2/2)]
z = 3 - 3i
Recall that cisθ = cosθ + i·sinθ
Hope this helped!
Sam B.
asked 04/19/23Convert the polar form of the complex number into rectangular form
z=3squrt2cis7pi/4
show work
show how you separately convert r and Thea into a and b
z = 3√2[cos(7π/4)+i·sin(7π/4)]
z = 3√2[√2/2 + i(-√2/2)]
z = 3 - 3i
Recall that cisθ = cosθ + i·sinθ
Hope this helped!
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