Inactive Tutor answered 04/14/23
1/F = 1/15 + 1/8.5; F = 15·8.5/(15 + 8.5) = 5.4255 cm
a.) 1/F = 1/d + 1/f; f = F·d/(d - F) = 5.4255·25/(25 - 5.4255) = 6.93cm
b.) h1/h = f1/d1; h2/h = f2/d2; m = h2/h1 = f2d1/(f1d2) = 6.93·15/(8.5·25) = 0.49
Charlotte A.
asked 04/14/23a.) If the light bulb is moved to a position 25 cm from the mirror, what is the position of the image?
b.) What are the magnifications of the first and final images?
Inactive Tutor answered 04/14/23
1/F = 1/15 + 1/8.5; F = 15·8.5/(15 + 8.5) = 5.4255 cm
a.) 1/F = 1/d + 1/f; f = F·d/(d - F) = 5.4255·25/(25 - 5.4255) = 6.93cm
b.) h1/h = f1/d1; h2/h = f2/d2; m = h2/h1 = f2d1/(f1d2) = 6.93·15/(8.5·25) = 0.49
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.