How do I solve this?

Question

A V-6 internal combustion engine burns fuel at the rate of 4.3 gallons per hour. The fuel has a heating value of 54.6 kJ/mL. Calculate the useful output power (in kilowatts) to the power train assuming an overall efficiency of 58%.

Answer 1

Use unit conversion and pseudoconversion (ratios of units that are specific to problem and are not universal - often connect different types of units like g/ml or kJ/ml)

(4.3 gal/hr)(4 qts/gal)(1 liter/1.0057 qt)(1000 ml/liter)(54.6 kJ/ml)(1hr/3600 s) = kJ/s or kW

Adjust for efficiency by multiplying by .58.

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