pre calc assignment help

Question

8x^2-12x-37/4x+6

the equation of the vertical vertical asymptote is X=

the equation of the slant asymptote is y=

Answer 1

(8x^2 -12x -37)/(4x+6) has vertical asymptote: x = -6/4 =-3/2, the x value that makes the denominator=0

to find another asymptote take the ratio of the leading terms of numerator & denominator y=8x^2/4x

y=2x

which is diagonal, not vertical or horizontal

a little more vertical than a 45 degree line with the x axis

call it the "slant" asymptote