Raymond B. answered 04/09/23
Math, microeconomics or criminal justice
zeros of 4x^3 -20x^2 +31x -21= (x-3)(4x^2-8x +7)
using decartes' rule of signs
possible 3 + zeros
no possible - zeros
try x=0,1,2,3 bingo
x=3 is the only real zero
2 imaginary zeros, they come in conjugate pairs
zeros are: 3, 1+.5isqr3, 1-.5isqr3